实现门锁的UI

JLChen

2021-05-14 3bedb23993745f97e5870eca160c9f00c053c44c

 HDL_ON/UI/UI2/FuntionControlView/DoorLock/DoorLockPage.cs

@@ -226,7 +226,7 @@
        private void InitUnLockMenuControl()
        {
            //如果是成员,则只有一键开锁
            if (DB_ResidenceData.Instance.CurrentRegion.IsOthreShare == true)
            if (DB_ResidenceData.Instance.CurrentRegion.isOtherShare == true)
            {
                //一键开锁
                var btnOneKey = new NormalViewControl(100, 25, true);
@@ -444,7 +444,7 @@
        private void InitBottomMenuIconControl()
        {
            //如果是成员,则只有开锁方式管理
            if (DB_ResidenceData.Instance.CurrentRegion.IsOthreShare == true)
            if (DB_ResidenceData.Instance.CurrentRegion.isOtherShare == true)
            {
                //开锁方式管理图标
                var btnManagerIcon = new IconViewControl(40);
@@ -849,7 +849,7 @@
            if (this.listMember != null) { return true; }

            //主账号需要去获取成员列表,而子账号只能他自己
            if (DB_ResidenceData.Instance.CurrentRegion.IsOthreShare == false)
            if (DB_ResidenceData.Instance.CurrentRegion.isOtherShare == false)
            {
                //获取成员列表
                var responePack = new DAL.Server.HttpServerRequest().GetResidenceMemberAccount();
@@ -874,7 +874,7 @@
            //自身加进去,自己位于首位
            var info = new ResidenceMemberInfo();
            info.childAccountId = OnAppConfig.Instance.LastLoginUserId;
            info.childAccountType = DB_ResidenceData.Instance.CurrentRegion.IsOthreShare == false ? "ADMIN" : "ORDINARY";
            info.childAccountType = DB_ResidenceData.Instance.CurrentRegion.isOtherShare == false ? "ADMIN" : "ORDINARY";
            info.nickName = UserInfo.Current.userName;
            this.listMember.Insert(0, info);
            if (string.IsNullOrEmpty(info.nickName))